# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right
class Solution:
def equalToDescendants(self, root: Optional[TreeNode]) -> int:
self.count=0
def dfs(node):
if not node:
return 0
add=dfs(node.left)+dfs(node.right)
if node.val==add:
self.count+=1
return add+node.val
dfs(root)
return self.count'알고리즘 문제 > Leetcode' 카테고리의 다른 글
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