알고리즘 문제/Leetcode
207. Course Schedule
BEstyle
2023. 3. 19. 15:04
There are a total of numCourses courses you have to take, labeled from 0 to numCourses - 1. You are given an array prerequisites where prerequisites[i] = [ai, bi] indicates that you must take course bi first if you want to take course ai.
- For example, the pair [0, 1], indicates that to take course 0 you have to first take course 1.
Return true if you can finish all courses. Otherwise, return false.
Example 1:
Input: numCourses = 2, prerequisites = [[1,0]]
Output: true
Explanation: There are a total of 2 courses to take.
To take course 1 you should have finished course 0. So it is possible.
Example 2:
Input: numCourses = 2, prerequisites = [[1,0],[0,1]]
Output: false
Explanation: There are a total of 2 courses to take.
To take course 1 you should have finished course 0, and to take course 0 you should also have finished course 1. So it is impossible.
Constraints:
- 1 <= numCourses <= 2000
- 0 <= prerequisites.length <= 5000
- prerequisites[i].length == 2
- 0 <= ai, bi < numCourses
- All the pairs prerequisites[i] are unique.
class Solution:
def canFinish(self, numCourses: int, prerequisites: List[List[int]]) -> bool:
courses = { i:[] for i in range(numCourses)}
for course, prereq in prerequisites:
courses[course].append(prereq)
print(courses)
visited = set()
def dfs(course):
if course in visited:
return False
if courses[course] == []:
return True
visited.add(course)
for pre in courses[course]:
if not dfs(pre):
return False
visited.remove(course)
courses[course] = []
return True
for course in range(numCourses):
if not dfs(course):
return False
return True