알고리즘 문제/Leetcode
1299. Replace Elements with Greatest Element on Right Side
BEstyle
2022. 12. 27. 18:39
Given an array arr, replace every element in that array with the greatest element among the elements to its right, and replace the last element with -1.
After doing so, return the array.
Example 1:
Input: arr = [17,18,5,4,6,1]
Output: [18,6,6,6,1,-1]
Explanation:
- index 0 --> the greatest element to the right of index 0 is index 1 (18).
- index 1 --> the greatest element to the right of index 1 is index 4 (6).
- index 2 --> the greatest element to the right of index 2 is index 4 (6).
- index 3 --> the greatest element to the right of index 3 is index 4 (6).
- index 4 --> the greatest element to the right of index 4 is index 5 (1).
- index 5 --> there are no elements to the right of index 5, so we put -1.
Example 2:
Input: arr = [400]
Output: [-1]
Explanation: There are no elements to the right of index 0.
Constraints:
- 1 <= arr.length <= 104
- 1 <= arr[i] <= 105
class Solution:
def replaceElements(self, arr: List[int]) -> List[int]:
ans=[0] * len(arr)
max=-1
for i in range(len(arr)-1,-1,-1):
ans[i]=max
if arr[i]>max:
max=arr[i]
return ans