Financing Plan on Planet XY140Z-n

DESCRIPTION:

I need to save some money to buy a gift. I think I can do something like that:

First week (W0) I save nothing on Sunday, 1 on Monday, 2 on Tuesday... 6 on Saturday, second week (W1) 2 on Monday... 7 on Saturday and so on according to the table below where the days are numbered from 0 to 6.

Can you tell me how much I will have for my gift on Saturday evening after I have saved 12? (Your function finance(6) should return 168 which is the sum of the savings in the table).

Imagine now that we live on planet XY140Z-n where the days of the week are numbered from 0 to n (integer n > 0) and where I save from week number 0 to week number n included (in the table below n = 6).

How much money would I have at the end of my financing plan on planet XY140Z-n?

--SuMoTuWeThFrSa

W6							12
W5						10	11
W4					8	9	10
W3				6	7	8	9
W2			4	5	6	7	8
W1		2	3	4	5	6	7
W0	0	1	2	3	4	5	6

Example:

finance(5) --> 105
finance(6) --> 168
finance(7) --> 252
finance(5000) --> 62537505000

Note:

your solution will be nicer without loops.

---

def finance(n):
    ans=0
    n=n+1
    for i in range(n):
        ans+=numw(n,i)
    return ans

    
def numw(num,week):
    ans=0
    for i in range(num-week):
        ans+=i+(2*week)
    return ans