Given the root of a binary tree, return the sum of values of nodes with an even-valued grandparent. If there are no nodes with an even-valued grandparent, return 0.
A grandparent of a node is the parent of its parent if it exists.
Example 1:
Input: root = [6,7,8,2,7,1,3,9,null,1,4,null,null,null,5]
Output: 18
Explanation: The red nodes are the nodes with even-value grandparent while the blue nodes are the even-value grandparents.
Example 2:
Input: root = [1]
Output: 0
Constraints:
- The number of nodes in the tree is in the range [1, 104].
- 1 <= Node.val <= 100
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right
class Solution:
def sumEvenGrandparent(self, root: TreeNode) -> int:
self.ans=0
def dfs(node, gp, p):
if not node:
return
if gp:
self.ans+=node.val
iseven=node.val%2==0
dfs(node.left, p, iseven)
dfs(node.right, p, iseven)
dfs(root,False,False)
return self.ans
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