Given an array of integers nums, return the number of good pairs.
A pair (i, j) is called good if nums[i] == nums[j] and i < j.
Example 1:
Input: nums = [1,2,3,1,1,3]
Output: 4
Explanation: There are 4 good pairs (0,3), (0,4), (3,4), (2,5) 0-indexed.
Example 2:
Input: nums = [1,1,1,1]
Output: 6
Explanation: Each pair in the array are good.
Example 3:
Input: nums = [1,2,3]
Output: 0
Constraints:
- 1 <= nums.length <= 100
- 1 <= nums[i] <= 100
class Solution:
def numIdenticalPairs(self, nums: List[int]) -> int:
def fac(n):
ans=0
while n!=0:
n-=1
ans+=n
return ans
c=Counter(nums)
ans=0
for k,v in c.items():
if v>=2:
ans+=(fac(v))
return ans
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