Consider all the leaves of a binary tree, from left to right order, the values of those leaves form a leaf value sequence.
For example, in the given tree above, the leaf value sequence is (6, 7, 4, 9, 8).
Two binary trees are considered leaf-similar if their leaf value sequence is the same.
Return true if and only if the two given trees with head nodes root1 and root2 are leaf-similar.
Example 1:
Input: root1 = [3,5,1,6,2,9,8,null,null,7,4], root2 = [3,5,1,6,7,4,2,null,null,null,null,null,null,9,8]
Output: true
Example 2:
Input: root1 = [1,2,3], root2 = [1,3,2]
Output: false
Constraints:
- The number of nodes in each tree will be in the range [1, 200].
- Both of the given trees will have values in the range [0, 200].
#https://leetcode.com/problems/leaf-similar-trees/description/
'''
1. 아이디어 :
1) dfs로 풀기.
2. 시간복잡도 :
1) O(n)
3. 자료구조 :
1) dfs
'''
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right
class Solution:
def leafSimilar(self, root1: Optional[TreeNode], root2: Optional[TreeNode]) -> bool:
def dfs(node,nums):
if node:
if node.left==None and node.right==None:
nums.append(node.val)
if node.left:
dfs(node.left,nums)
if node.right:
dfs(node.right, nums)
return nums
return dfs(root1,[]) == dfs(root2,[])
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