물음표 살인마의 개발블로그

알고리즘 문제/Leetcode

21. Merge Two Sorted Lists

BEstyle 2022. 12. 29. 02:50

You are given the heads of two sorted linked lists list1 and list2.

Merge the two lists in a one sorted list. The list should be made by splicing together the nodes of the first two lists.

Return the head of the merged linked list.

 

Example 1:

Input: list1 = [1,2,4], list2 = [1,3,4]
Output: [1,1,2,3,4,4]

Example 2:

Input: list1 = [], list2 = []
Output: []

Example 3:

Input: list1 = [], list2 = [0]
Output: [0]

 

Constraints:

  • The number of nodes in both lists is in the range [0, 50].
  • -100 <= Node.val <= 100
  • Both list1 and list2 are sorted in non-decreasing order.

# Definition for singly-linked list.
# class ListNode:
#     def __init__(self, val=0, next=None):
#         self.val = val
#         self.next = next
class Solution:
    def mergeTwoLists(self, list1: Optional[ListNode], list2: Optional[ListNode]) -> Optional[ListNode]:
        tail=ListNode(-1)
        head=tail
        
        current1=list1
        current2=list2

        while current1 and current2:
            if current1.val<=current2.val:
                tail.next=current1
                current1=current1.next
            else:
                tail.next=current2
                current2=current2.next
            tail=tail.next
        tail.next = current1 if current1 else current2
        return head.next