Given a string s, find the length of the longest
without repeating characters.
Example 1:
Input: s = "abcabcbb"
Output: 3
Explanation: The answer is "abc", with the length of 3.
Example 2:
Input: s = "bbbbb"
Output: 1
Explanation: The answer is "b", with the length of 1.
Example 3:
Input: s = "pwwkew"
Output: 3
Explanation: The answer is "wke", with the length of 3.
Notice that the answer must be a substring, "pwke" is a subsequence and not a substring.
Constraints:
- 0 <= s.length <= 5 * 104
- s consists of English letters, digits, symbols and spaces.
class Solution:
def lengthOfLongestSubstring(self, s: str) -> int:
if len(s)<=1:
return len(s)
lp=0
rp=0
longest=""
clongest=""
while rp<len(s):
if s[rp] not in clongest:
clongest+=s[rp]
rp+=1
else:
if len(longest)<len(clongest):
longest=clongest
clongest = clongest[clongest.index(s[rp])+1:]
return max(len(longest),len(clongest))'알고리즘 문제 > Leetcode' 카테고리의 다른 글
| 682. Baseball Game (0) | 2022.12.28 |
|---|---|
| 844. Backspace String Compare (2) | 2022.12.28 |
| 283. Move Zeroes (0) | 2022.12.28 |
| 88. Merge Sorted Array (0) | 2022.12.27 |
| 1984. Minimum Difference Between Highest and Lowest of K Scores (0) | 2022.12.27 |