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알고리즘 문제/Leetcode

2027. Minimum Moves to Convert String

BEstyle 2022. 12. 3. 18:59

You are given a string s consisting of n characters which are either 'X' or 'O'.

A move is defined as selecting three consecutive characters of s and converting them to 'O'. Note that if a move is applied to the character 'O', it will stay the same.

Return the minimum number of moves required so that all the characters of s are converted to 'O'.

 

Example 1:

Input: s = "XXX"
Output: 1
Explanation: XXX -> OOO
We select all the 3 characters and convert them in one move.

Example 2:

Input: s = "XXOX"
Output: 2
Explanation: XXOX -> OOOX -> OOOO
We select the first 3 characters in the first move, and convert them to 'O'.
Then we select the last 3 characters and convert them so that the final string contains all 'O's.

Example 3:

Input: s = "OOOO"
Output: 0
Explanation: There are no 'X's in s to convert.

 

Constraints:

  • 3 <= s.length <= 1000
  • s[i] is either 'X' or 'O'.
  •  

class Solution:
    def minimumMoves(self, s: str) -> int:
        count=0
        while len(s)>=3:
            if s[0]=="O":
                s=s[1:]
            elif s[0]=="X" or s[1]=="X" or s[2]=="X":
                count+=1
                s=s[3:]
        if "X" in s:
            count+=1
        return count