Given an integer array nums, return the largest perimeter of a triangle with a non-zero area, formed from three of these lengths. If it is impossible to form any triangle of a non-zero area, return 0.
Example 1:
Input: nums = [2,1,2]
Output: 5
Explanation: You can form a triangle with three side lengths: 1, 2, and 2.
Example 2:
Input: nums = [1,2,1,10]
Output: 0
Explanation:
You cannot use the side lengths 1, 1, and 2 to form a triangle.
You cannot use the side lengths 1, 1, and 10 to form a triangle.
You cannot use the side lengths 1, 2, and 10 to form a triangle.
As we cannot use any three side lengths to form a triangle of non-zero area, we return 0.
Constraints:
- 3 <= nums.length <= 104
- 1 <= nums[i] <= 106
class Solution:
def largestPerimeter(self, nums: List[int]) -> int:
nums=sorted(nums)[::-1]
for i in range(0,len(nums)-2):
if nums[i+2]+nums[i+1]>nums[i]:
return nums[i+2]+nums[i+1]+nums[i]
return 0
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